mq005.二叉树的层序遍历 Leetcode binaryTree bfs Nov 04, 2020 题目链接 此题与lc102一样。这个算法的时间复杂度是O(N),空间复杂度是O(N)。 # Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def levelOrder(self, root: TreeNode) -> List[List[int]]: if not root: return [] res, stack = [], [root] while stack: seg = [] for i in range(len(stack)): tmp = stack.pop(0) seg.append(tmp.val) if tmp.left: stack.append(tmp.left) if tmp.right: stack.append(tmp.right) res.append(seg) return res PREVIOUSmq004.验证回文串NEXTmq006.复制带随机指针的列表