lc110.平衡二叉树 Leetcode BinaryTree Oct 14, 2020 题目链接 这个题和jz055II相似。这个算法的时间复杂度是O(N),空间复杂度是O(N)。 # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def isBalanced(self, root: TreeNode) -> bool: def dfs(node): if not node: return 0 left = dfs(node.left) if left == -1: return -1 right = dfs(node.right) if right == -1: return -1 return max(left, right) + 1 if abs(left - right) <= 1 else -1 return dfs(root) != -1 PREVIOUSjz056I.数组中数字出现的次数NEXTlc136.只出现一次的数字