lc113.路径总和II Leetcode stack dfs Jun 20, 2020 题目链接 此题与jz034.二叉树中和为某一值的路径相同,这个算法的时间复杂度是O(N),空间复杂度是O(N)。 # Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def pathSum(self, root: TreeNode, tar: int) -> List[List[int]]: stack, res = [], [] def dfs(node): if not node: return stack.append(node.val) if not node.left and not node.right and sum(stack) == tar: res.append(list(stack)) dfs(node.left) dfs(node.right) stack.pop() dfs(root) return res PREVIOUSjz034.二叉树中和为某一值的路径NEXTjz035.复杂链表的复制